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Sáng Nguyễn Xuân

28/03/2018 at 11:47
Answers
2
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For two polynomials: \(f\left(x\right)=x^3-4x^2-7x-1\) and \(g\left(x\right)=x^4+x^3-x^2-7x+2\)

a, Calculated \(f\left(2\right)\) và \(g\left(\dfrac{1}{2}\right)\)

b, Indicate that \(f\left(x\right)-g\left(x\right)\)

Always accepts negative values ​​for every value of the variable




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  • ...
    Dao Trong Luan Coordinator 28/03/2018 at 12:20

    a, \(f\left(2\right)=2^3-4.2^2-7.2-1=8-16-14-1=-23\)

    \(g\left(\dfrac{1}{2}\right)=\left(\dfrac{1}{2}\right)^4+\left(\dfrac{1}{2}\right)^3-\left(\dfrac{1}{2}\right)^2-7.\dfrac{1}{2}+2=\dfrac{1}{16}+\dfrac{1}{8}-\dfrac{1}{4}-\dfrac{7}{2}+2=-\dfrac{25}{16}\)

    b,

    \(f\left(x\right)-g\left(x\right)=x^3-4x^2-7x-1-\left(x^4+x^3-x^2-7x+2\right)\)

    \(=x^3-4x^2-7x-1-x^4-x^3+x^2+7x-2\)

    \(=-x^4-3x^2-3\)

    Sáng Nguyễn Xuân selected this answer.
  • ...
    ¤« 02/04/2018 at 13:13

    a, f(2)=23−4.22−7.2−1=8−16−14−1=−23

    g(12)=(12)4+(12)3−(12)2−7.12+2=116+18−14−72+2=−2516

    b,

    f(x)−g(x)=x3−4x2−7x−1−(x4+x3−x2−7x+2)

    =x3−4x2−7x−1−x4−x3+x2+7x−2

    =−x4−3x2−3


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