Lê Anh Duy
12/03/2018 at 15:32-
FC Alan Walker 16/03/2018 at 10:28
We have: \(x^2\) is a square number
\(\Rightarrow x\in Z\)
-C1: \(x⋮3\)
\(\Rightarrow x^2\equiv0\) (mod 3)
\(\Rightarrow x^2+5\equiv2\) (mod 3) (Impossible because \(x^2+5\) is a square number)
-C2: \(x⋮̸3\)
\(\Rightarrow x^2\equiv1\) (mod 3)
\(\Rightarrow x^2-5\equiv2\) (mod 3) (Impossible because \(x^2-5\) is a square number)
So can't find x.
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Lê Anh Duy 19/03/2018 at 13:44
Your answer is incorrect, try again
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