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Lê Quốc Trần Anh Coordinator

07/03/2018 at 04:27
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Alysha’s average speed when walking from home to the market is 5 mi/h, and it takes her 21 minutes longer than when she drives to the market. If Alysha drives to the market, along the same route, at an average speed that is eight times her average walking speed, how many minutes does it take her to drive from home to the market?




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  • ...
    Doan Le Minh Hong moderators 09/03/2018 at 15:22

    Let the average driving speed be \(v\) and the time it takes Alysha to drive to the market be \(t\).

    So, we have the length of the route from home to the market is: \(v \times t\).

    Because the average driving speed is 8 times the average walking speed, we have the average walking speed is: \(\dfrac{v}{8}\).

    Therefore, the time it takes Alysha to walk to the market is:\(\dfrac{v \times t}{\dfrac{v}{8}}=\dfrac{8 \times v \times t}{v}=8t\).

    We can see that walking takes her 21 minutes longer than when she drives to the market; thus, the difference between the walking time and the driving time is: \(8t-t=7t\).

    \(\Rightarrow 7t=21 \Rightarrow t=3\).

    Thus, it takes her 3 minutes to drive from home to market.

    Lê Quốc Trần Anh selected this answer.
  • ...
    ¤« 11/03/2018 at 09:35

    Let the average driving speed be v and the time it takes Alysha to drive to the market be t

    .

    So, we have the length of the route from home to the market is: v×t

    .

    Because the average driving speed is 8 times the average walking speed, we have the average walking speed is: v8

    .

    Therefore, the time it takes Alysha to walk to the market is:v×tv8=8×v×tv=8t

    .

    We can see that walking takes her 21 minutes longer than when she drives to the market; thus, the difference between the walking time and the driving time is: 8t−t=7t

    .

    ⇒7t=21⇒t=3

    .

    Thus, it takes her 3 minutes to drive from home to market.


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