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Jacob 05/03/2018 at 02:22The stage ith is \(i^2\)
So the number of dots at stage 47 is more than at the stage 27 is:
\(47^2-27^2=\left(47-27\right)\left(47+27\right)=20.74=1480\)
Lê Quốc Trần Anh selected this answer.
The stage ith is \(i^2\)
So the number of dots at stage 47 is more than at the stage 27 is:
\(47^2-27^2=\left(47-27\right)\left(47+27\right)=20.74=1480\)
Lê Quốc Trần Anh selected this answer.