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Jacob 05/03/2018 at 02:41Call a, b, c be sides of the triangle, we have
\(\dfrac{a}{11}=\dfrac{b}{8}=\dfrac{c}{6}=\dfrac{a+b+c}{11+8+6}=\dfrac{100}{25}=4\)
=> a = 44, b = 32, c = 24
Call a, b, c be sides of the triangle, we have
\(\dfrac{a}{11}=\dfrac{b}{8}=\dfrac{c}{6}=\dfrac{a+b+c}{11+8+6}=\dfrac{100}{25}=4\)
=> a = 44, b = 32, c = 24