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Anna

27/02/2018 at 08:21
Answers
3
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Give a test for divisibility by 4 in the decimal system.




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  • ...
    Emma 27/02/2018 at 09:24

    We have:

    \(\overline{a_na_{n-1}...a_3a_2a_1}=\overline{a_na_{n-1}..a_4}.1000+\overline{a_3a_2a_1}\)

    Since \(1000⋮4\) => \(\overline{a_na_{n-1}..a_4}.1000\) \(⋮\) \(4\).

    \(\overline{a_na_{n-1}...a_3a_2a_1}\)  \(⋮\) \(4\)  iff   \(\overline{a_3a_2a_1}\) \(⋮\)  \(4\)

    In other word: a number is divisibility by 4 if only if the number formed by its three right digits is divisibility by 4.

  • ...
    ¤« 28/02/2018 at 16:04

    Another way:

    We have: ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯xnxn−1...x3x2x1=100.¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯xnxn−1...x3+¯¯¯¯¯¯¯¯¯¯¯x2x1

    Since 100⋮4

    =>100.¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯xnxn−1...x3⋮4

    ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯xnxn−1...x3x2x1⋮4

    =>¯¯¯¯¯¯¯¯¯¯¯x2x1⋮4

    In other word: a number is divisibility by 4 when the last three digits on the right-hand is divisibility by 4

  • ...
    FC Alan Walker 28/02/2018 at 08:38

    Another way:

    We have: \(\overline{x_nx_{n-1}...x_3x_2x_1}=100.\overline{x_nx_{n-1}...x_3}+\overline{x_2x_1}\)

    Since \(100⋮4\)=>\(100.\overline{x_nx_{n-1}...x_3}⋮4\)

    \(\overline{x_nx_{n-1}...x_3x_2x_1}⋮4\)=>\(\overline{x_2x_1}⋮4\)

    In other word: a number is divisibility by 4 when the last three digits on the right-hand is divisibility by 4


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