Question by Anna - Discuss with MathYouLike

Anna

27/02/2018 at 08:17

If N = p^k (where p is a prime number and k is a counting number), how many factors does N have?

List of answers

¤« 27/02/2018 at 12:27

Factors of N: {1, p, p2, ...., pk-1, pk }

=> There are k + 1 factors.
Emma 27/02/2018 at 09:15

Factors of N: {1, p, p², ...., p^k-1, p^k }

=> There are k + 1 factors.

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