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Fc Alan Walker

19/02/2018 at 21:15
Answers
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solution of the equation :

\(\dfrac{x-35}{21}+\dfrac{x-36}{20}>\dfrac{x-37}{19}+\dfrac{x-38}{18}\)


Simulataneous Equation A System of Equations


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    ¤« 19/02/2018 at 21:28

    We have :

    \(\dfrac{x-35}{21}+\dfrac{x-36}{20}>\dfrac{x-37}{19}+\dfrac{x-38}{18}\)

    \(\left(\dfrac{x-35}{21}-1\right)+\left(\dfrac{x-36}{20}-1\right)>\left(\dfrac{x-37}{19}-1\right)+\left(\dfrac{x-38}{18}-1\right)\)

    \(\dfrac{x-56}{21}+\dfrac{x-56}{20}>\dfrac{x-56}{19}+\dfrac{x-56}{18}\)

    \(\dfrac{x-56}{21}+\dfrac{x-56}{20}-\dfrac{x-50}{19}-\dfrac{x-50}{18}>0\)

    \(\left(x-56\right)\left(\dfrac{1}{21}+\dfrac{1}{20}-\dfrac{1}{19}-\dfrac{1}{18}\right)>0\)

    To \(\dfrac{1}{21}+\dfrac{1}{20}-\dfrac{1}{19}-\dfrac{1}{18}\) different 0

    \(x-56< 0\)

    \(x< 56\)
     


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