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Đội bóng tia chớp FC

13/01/2018 at 21:31
Answers
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Polynomial analysis into multiplication and find x :

\(x^3-x^2+x-1=0\)

\(x\left(x^2-16\right)-2\left(x^2-16\right)=0\)




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  • ...
    FA FIFA Club World Cup 2018 13/01/2018 at 21:37

    a , \(x^2\left(x-1\right)+\left(x-1\right)=0\)

    \(\left(x-1\right)\left(x^2+1\right)=0\)

    \(x=1\)

    b , \(\left(x-2\right)\left(x^2-16\right)=0\)

    \(\left(x-2\right)\left(x-4\right)\left(x+4\right)=0\)

    \(x=2,x=4,x=4\)

  • ...
    Fc Alan Walker 22/01/2018 at 12:30

    a , x2(x−1)+(x−1)=0

    (x−1)(x2+1)=0

    x=1

    b , (x−2)(x2−16)=0

    (x−2)(x−4)(x+4)=0

    x=2,x=4,x=4


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