Donald Trump
20/03/2017 at 13:42-
FA KAKALOTS 19/02/2018 at 20:52Given a sum : 2 + 4 + 6 + ... + 2k
The number of terms is : 2k−22+1=k
( terms )
So, the result of this sum is : k.(2k+2)2=k.(k+1)
Example : 2 + 4 + 6 = 2 + 4 + 2.3 ; so k = 3; then 2 + 4 +6 = k.(k+1)=3.4 .
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Indratreinpro 05/04/2017 at 13:13Given a sum : 2 + 4 + 6 + ... + 2k
The number of terms is : 2k−22+1=k2k−22+1=k ( terms )
So, the result of this sum is : k.(2k+2)2=k.(k+1)k.(2k+2)2=k.(k+1)
Example : 2 + 4 + 6 = 2 + 4 + 2.3 ; so k = 3; then 2 + 4 +6 = k.(k+1)=3.4 .
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Run my EDM 21/03/2017 at 21:17Given a sum : 2 + 4 + 6 + ... + 2k
The number of terms is : \(\dfrac{2k-2}{2}+1=k\) ( terms )
So, the result of this sum is : \(\dfrac{k.\left(2k+2\right)}{2}=k.\left(k+1\right)\)
Example : 2 + 4 + 6 = 2 + 4 + 2.3 ; so k = 3; then 2 + 4 +6 = k.(k+1)=3.4 .