3 diagonals of the hexagon which are the diameters of the circle divide the hexagon into 6 congruent equilateral triangles. The area of each equilateral triangle is : (4√3)2.√34=12√3

 (cm2)

The answer is : 12√3.6=72√3

 (cm2)

3 diagonals of the hexagon which are the diameters of the circle divide the hexagon into 6 congruent equilateral triangles. The area of each equilateral triangle is : \(\dfrac{\left(4\sqrt{3}\right)^2.\sqrt{3}}{4}=12\sqrt{3}\) (cm²)

The answer is : \(12\sqrt{3}.6=72\sqrt{3}\) (cm²)