Let a, b be the side length of each poygon respectively (a,b∈Z+)

{6a=8b6a+8b<200⇒⎧⎨⎩ab=4312a<200

⇒⎧⎪⎨⎪⎩a⋮4(b⋮3)a<17

The answer is : (16 - 4) : 4 + 1 = 4

Let a, b be the side length of each poygon respectively \(\left(a,b\in Z^+\right)\)

\(\left\{{}\begin{matrix}6a=8b\\6a+8b< 200\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\dfrac{a}{b}=\dfrac{4}{3}\\12a< 200\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a⋮4\left(b⋮3\right)\\a< 17\end{matrix}\right.\)

The answer is : (16 - 4) : 4 + 1 = 4