Lê Quốc Trần Anh Coordinator
03/01/2018 at 17:02-
\(\sqrt{2+4+6+x}\) (Condition \(-12\le x< 8\)).
\(\Leftrightarrow\sqrt{12+x}=n\left(n\in N\right)\)
So x will satisfy \(x=\left\{-12;-11;-8;-3;4\right\}\)
The sum of \(x=-12-11-8-3+4=-30\)
Answer : - 30.
Lê Quốc Trần Anh selected this answer. -
FA Liên Quân Garena 08/01/2018 at 21:48√2+4+6+x (Condition −12≤x<8
).
⇔√12+x=n(n∈N)
So x will satisfy x={−12;−11;−8;−3;4}
The sum of x=−12−11−8−3+4=−30
Answer : - 30.
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Asuna Yuuki 04/01/2018 at 15:52√2+4+6+x2+4+6+x (Condition −12≤x<8−12≤x<8).
⇔√12+x=n(n∈N)⇔12+x=n(n∈N)
So x will satisfy x={−12;−11;−8;−3;4}x={−12;−11;−8;−3;4}
The sum of x=−12−11−8−3+4=−30x=−12−11−8−3+4=−30
Answer : - 30.