MathYouLike MathYouLike
  • Toggle menubar
  • Toggle fullscreen
  • Toggle Search
  •    Sign up
  • QUESTIONS
  • TAGS
  • USERS
  • BADGES
  • UNANSWERD
  • ASK A QUESTION
  • BLOG
...

Lê Quốc Trần Anh Coordinator

03/01/2018 at 16:54
Answers
2
Follow

What is the product of the roots of \(64x+16x^2-4x^3-x^4=0\)?




    List of answers
  • ...
    Alone 03/01/2018 at 17:01

    We have:\(64x+16x^2-4x^3-x^4=0\)

    \(\Leftrightarrow16x\left(x+4\right)-x^3\left(x+4\right)=0\)

    \(\Leftrightarrow\left(16x-x^3\right)\left(x+4\right)=0\)

    \(\Leftrightarrow x\left(x+4\right)\left(16-x^2\right)=0\)

    \(\Leftrightarrow x\left(4-x\right)\left(x+4\right)^2=0\)

    \(\Rightarrow\left[{}\begin{matrix}x=0\\4-x=0\\x+4=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=0\\x=4\\x=-4\end{matrix}\right.\)

    Lê Quốc Trần Anh selected this answer.
  • ...
    FA Liên Quân Garena 08/01/2018 at 21:50

    We have:64x+16x2−4x3−x4=0

    ⇔16x(x+4)−x3(x+4)=0

    ⇔(16x−x3)(x+4)=0

    ⇔x(x+4)(16−x2)=0

    ⇔x(4−x)(x+4)2=0

    ⇒⎡⎢⎣x=04−x=0x+4=0

    ⇒⎡⎢⎣x=0x=4x=−4


Post your answer

Please help Lê Quốc Trần Anh to solve this problem!



Weekly ranking


© HCEM 10.1.29.225
Crafted with by HCEM