nguyenlong
30/12/2017 at 15:55-
Help you solve math 30/12/2017 at 16:02
\(\dfrac{2010}{2}\) + \(\dfrac{2010}{6}\) + \(\dfrac{2010}{12}\) + ... + \(\dfrac{2010}{9900}\)
= 2010 . \(\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right)\)
= 2010 . \(\left(1-\dfrac{1}{100}\right)\)
= 1989,9
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FA Liên Quân Garena 30/12/2017 at 21:27
2010220102 + 2010620106 + 201012201012 + ... + 2010990020109900
= 2010 . (11.2+12.3+13.4+...+199.100)(11.2+12.3+13.4+...+199.100)
= 2010 . (1−1100)(1−1100)
= 1989,9