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nguyenlong

30/12/2017 at 15:55
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\(\dfrac{2010}{2}\) + \(\dfrac{2010}{6}\) + \(\dfrac{2010}{12}\) + ... + \(\dfrac{2010}{9900}\) = ?




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    Help you solve math 30/12/2017 at 16:02

    \(\dfrac{2010}{2}\) + \(\dfrac{2010}{6}\) + \(\dfrac{2010}{12}\) + ... + \(\dfrac{2010}{9900}\)

    = 2010 . \(\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right)\)

    = 2010 . \(\left(1-\dfrac{1}{100}\right)\) 

    = 1989,9

  • ...
    FA Liên Quân Garena 30/12/2017 at 21:27

    2010220102 + 2010620106 + 201012201012 + ... + 2010990020109900

    = 2010 . (11.2+12.3+13.4+...+199.100)(11.2+12.3+13.4+...+199.100)

    = 2010 . (1−1100)(1−1100) 

    = 1989,9


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