DJ Shape of you
27/12/2017 at 19:32-
KEITA FC 8C 27/12/2017 at 19:43\(M=a^2-3ab^2+2b^2\)
\(M=a\left(a^2-b^2\right)+2b^2\left(b-a\right)\)
\(M=\left(a-b\right)\left(a^2+ab-2b^2\right)\)
\(M=\left(a-b\right)\left[a^2-b^2+b\left(a-b\right)\right]\)
\(M=\left(a-b\right)^2\left(a+2b\right)\)
to \(a\ge0,b\ge0\) Candles \(M\ge0\)
Selected by MathYouLike -
Alone 27/12/2017 at 19:51KEITA FC 8C:You are wrong
a2-3ab2+2b2=a(a2-b2)+2b2(b-a)..........You are very stupid
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Alone 27/12/2017 at 19:48
KEITA FC 8C : Bạn sai.
một 2 -3ab 2 + 2b 2 = a (a 2 -b 2 ) + 2b 2 (ba) .... Bạn rất ngu ngốc