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Trần Thủy Tiên 26/12/2017 at 15:50
a)
2√a2−5a=2|a|−5a2a2−5a=2|a|−5a
2|a|−5a=−2a−5a=−7a2|a|−5a=−2a−5a=−7a
b)
√9a4+3a2=3|a2|+3a2=6a29a4+3a2=3|a2|+3a2=6a2
because a2≥0∀aϵR⇔|a2|=a2a2≥0∀aϵR⇔|a2|=a2
c)
√25a2+3a=5|a|+3a=5a+3a=8a25a2+3a=5|a|+3a=5a+3a=8a
because a≥0⇒|a|=aa≥0⇒|a|=a
d)
5√4a6−3a354a6−3a3
=5.2.|a3|−3a3=5.2.|a3|−3a3
=10.(−a)3−3a3=−13a3=10.(−a)3−3a3=−13a3
because a<0a<0 so |a3|=−a3
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KEITA FC 8C 27/12/2017 at 19:14
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a)
2√a2−5a=2|a|−5a2a2−5a=2|a|−5a
2|a|−5a=−2a−5a=−7a2|a|−5a=−2a−5a=−7a
b)
√9a4+3a2=3|a2|+3a2=6a29a4+3a2=3|a2|+3a2=6a2
because a2≥0∀aϵR⇔|a2|=a2a2≥0∀aϵR⇔|a2|=a2
c)
√25a2+3a=5|a|+3a=5a+3a=8a25a2+3a=5|a|+3a=5a+3a=8a
because a≥0⇒|a|=aa≥0⇒|a|=a
d)
5√4a6−3a354a6−3a3
=5.2.|a3|−3a3=5.2.|a3|−3a3
=10.(−a)3−3a3=−13a3=10.(−a)3−3a3=−13a3
because a<0a<0 so |a3|=−a3
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