MathYouLike MathYouLike
  • Toggle menubar
  • Toggle fullscreen
  • Toggle Search
  •    Sign up
  • QUESTIONS
  • TAGS
  • USERS
  • BADGES
  • UNANSWERD
  • ASK A QUESTION
  • BLOG
...

Kaya Renger Coordinator

18/12/2017 at 10:18
Answers
1
Follow

Given 2 straight lines AB and CD

Show that : If  \(AB\perp CD\) then AC2 - AD2 = BC2 - BD2




    List of answers
  • ...
    Dao Trong Luan Coordinator 18/12/2017 at 15:59

    A B C D H

    Put H is intersection of AB and CD

    \(\Rightarrow\left\{{}\begin{matrix}\left\{{}\begin{matrix}AC^2=HC^2+AH^2\\AD^2=HD^2+AH^2\end{matrix}\right.\Rightarrow AC^2-AD^2=\left(HC^2+AH^2\right)-\left(HD^2+AH^2\right)=HC^2-HD^2\\\left\{{}\begin{matrix}BC^2=HC^2+BH^2\\BD^2=HD^2+BH^2\end{matrix}\right.\Rightarrow BC^2-BD^2=\left(HC^2+BH^2\right)-\left(HD^2+BH^2\right)=HC^2-HD^2\end{matrix}\right.\)

    => AC2 - AD2 = BC2 - BD2

    Selected by MathYouLike

Post your answer

Please help Kaya Renger to solve this problem!



Weekly ranking


© HCEM 10.1.29.225
Crafted with by HCEM