Question by Nguyễn Phương Chinh - Discuss with MathYouLike

Nguyễn Phương Chinh

14/12/2017 at 23:12

The equation \(\dfrac{24x^2+25x-47}{ax-2}\) = -8x - 3 - \(\dfrac{53}{ax-2}\) is true for all values of x \(\ne\dfrac{2}{a}\), where a is a constant. What is the value of a?

A) -16

B) -3

C) 3

D) 16

SAT math-english

List of answers

Vũ Mạnh Hùng 24/12/2017 at 14:11

MY ANSWER IS:C
KEITA FC 8C 15/12/2017 at 20:57

The answer is C

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