In square WXYZ, point V is the midpoint of side YZ, and the area of \(\Delta\)XYV is unit\(^2\). What is the area of square WXYZ? Express your answer as a common fraction.
\(S_{WXYZ}=XY.YZ=XY.2VY=4.\dfrac{XY.VY}{2}=4S_{XYV}=4.\dfrac{4}{5}=\dfrac{16}{5}\) (unit2)
