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In each hundreds from 222 - 999, there are \(299-222+1=78\left(extensions\right)\)/each hundreds
From 222 - 999 there are: \(9-2+1=8\left(hundreds\right)\)
So there are: \(78\cdot8=624\) unique three-digit extensions can be assigned.
Selected by MathYouLike -
KEITA FC 8C 19/12/2017 at 12:49
In each hundreds from 222 - 999, there are 299−222+1=78(extensions)299−222+1=78(extensions)/each hundreds
From 222 - 999 there are: 9−2+1=8(hundreds)9−2+1=8(hundreds)
So there are: 78⋅8=62478⋅8=624 unique three-digit extensions can be assigned.