Question by Cloud - Discuss with MathYouLike

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08/12/2017 at 08:45

Adam has a triangle with vertices labeled 1 through 3. Jayvon has an octagon with vertices labeled 1 through 8. Each boy starts at position 1 and counts consecutive vertices on his polygon, continuing in the same direction, until he has reached 120 and is back at the vertex labeled 1. Percy did the same activity with his polygon, and he also finished at the vertex labeled 1. If Percy’s polygon is not a triangle or an octagon, what is the sum of all the possible numbers of sides his polygon might have?

List of answers

Phan Thanh Tinh Coordinator 15/01/2018 at 22:06

The sum of the factors of 120 which are different from 3 and 8 is :

4 + 5 + 6 + 10 + 12 + 15 + 20 + 24 + 30 + 40 + 60 + 120 = 346

So, the answer is 346

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