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05/12/2017 at 15:28

In the figure, regular pentagons ABCDE and VWXYZ have the same center. Each side of pentagon ABCDE is the hypotenuse of an isosceles right triangle. In each right triangle, the vertex opposite the hypotenuse is a vertex of pentagon VWXYZ. Each side of the smaller regular pentagon VWXYZ is also the base of one of the shaded acute isosceles triangles. What is the degree measure of the vertex angle of each shaded triangle?
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Phan Thanh Tinh Coordinator 15/01/2018 at 22:33

The answer is :

\(\widehat{VEZ}=\widehat{AED}-\widehat{AEV}-\widehat{DEZ}=\dfrac{180^0.3}{5}-45^0-45^0=18^0\)

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