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Nguyễn Hưng Phát 01/12/2017 at 17:06
If a=12,b=4,c=5 and x=\(\dfrac{1}{2}\) so \(\dfrac{\left(\dfrac{abc}{x}\right)-\left(6b^2-4\right)}{0,5}\)\(=\dfrac{\left(\dfrac{12.4.5}{\dfrac{1}{2}}\right)-\left(6.4^2-4\right)}{0,5}\)
\(=\dfrac{\left(\dfrac{240}{\dfrac{1}{2}}\right)-\left(96-4\right)}{0,5}=\dfrac{480-92}{0,5}=\dfrac{388}{\dfrac{1}{2}}=388.2=776\)
Answer:776`
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