We can only solve this question with the equation: \(y=ax^b\)

We have: \(8=1\cdot2^3\) ; \(27=1\cdot3^3\) ; \(125=1\cdot5^3\) ; \(216=1\cdot6^3\)

So a = 1 and b = 3 satisfy this question.

So their sum is: 1 + 3 = 4

the sum is :1+3=4

We have : \(\left\{{}\begin{matrix}8=a.2^b\\27=a.3^b\end{matrix}\right.\)\(\Rightarrow\dfrac{2^b}{3^b}=\dfrac{8}{27}\Rightarrow\left(\dfrac{2}{3}\right)^b=\left(\dfrac{2}{3}\right)^3\Rightarrow b=3\Rightarrow a=1\)

So, a + b = 4