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Let a, a + 1, a + 2, ... , a + 10 be the integers. We have :
\(a+\left(a+1\right)+\left(a+2\right)+...+\left(a+10\right)=11\)
\(\Leftrightarrow11a+\dfrac{10.11}{2}=11\Leftrightarrow a+\dfrac{10}{2}=1\Leftrightarrow a=-4\)
So, the answer is -4
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