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Cloud moderators

30/11/2017 at 13:48
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The sum of eleven consecutive integers is 11. What is the least of these eleven integers?




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    Phan Thanh Tinh Coordinator 30/11/2017 at 19:25

    Let a, a + 1, a + 2, ... , a + 10 be the integers. We have :

    \(a+\left(a+1\right)+\left(a+2\right)+...+\left(a+10\right)=11\)

    \(\Leftrightarrow11a+\dfrac{10.11}{2}=11\Leftrightarrow a+\dfrac{10}{2}=1\Leftrightarrow a=-4\)

    So, the answer is -4

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