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donald trump

19/03/2017 at 15:25
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A 6-digit number, 53ab98, is divisible by 99. Find the values of a and b.


divisibility


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    ¤« 03/04/2018 at 13:41

    0≤a,b≤9⇒−9≤a−b≤9;a+b≤18

    We have 53ab98¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯⋮99

    ,so :

    + 53ab98¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯⋮9⇒25+a+b⋮9⇒a+b=2;11

    +53ab98¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯⋮11⇒|5+a+9−3−b−8|=|3+a−b|⋮11

    ⇒a−b=−3;8

    If a + b = 2,then a + b is even but 2b is even

    => a + b - 2b = a - b is even => a - b = 8 > a + b (absurd)

    =>{a+b=11a−b=−3⇒{2a=8b=11−a

    ⇒{a=4b=7

  • ...
    Phan Thanh Tinh Coordinator 24/04/2017 at 23:30

    \(0\le a,b\le9\Rightarrow-9\le a-b\le9;a+b\le18\)

    We have \(\overline{53ab98}⋮99\),so :

    + \(\overline{53ab98}⋮9\Rightarrow25+a+b⋮9\Rightarrow a+b=2;11\)

    +\(\overline{53ab98}⋮11\Rightarrow\left|5+a+9-3-b-8\right|=\left|3+a-b\right|⋮11\)

    \(\Rightarrow a-b=-3;8\)

    If a + b = 2,then a + b is even but 2b is even

    => a + b - 2b = a - b is even => a - b = 8 > a + b (absurd)

    =>\(\left\{{}\begin{matrix}a+b=11\\a-b=-3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2a=8\\b=11-a\end{matrix}\right.\)

    \(\Rightarrow\left\{{}\begin{matrix}a=4\\b=7\end{matrix}\right.\)


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