Question by Monster girls - Discuss with MathYouLike

Monster girls

29/11/2017 at 15:39

Give: \(a+b+c\ge abc\).Prove that:

\(a^2+b^2+c^2\ge abc\)

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Dao Trong Luan Coordinator 29/11/2017 at 18:10

\(\left\{{}\begin{matrix}a\le a^2\\b\le b^2\\c\le c^2\end{matrix}\right.\Rightarrow a^2+b^2+c^2\ge a+b+c\ge abc\)

So \(a^2+b^2+c^2\ge abc\)
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