Summer Clouds moderators
28/11/2017 at 10:21-
Let a (cm) be the width of the small rectangles, then 2a is their length and the perimeter of the rectangle PQRS is : 2(2a + a + 2a) = 10a
The area of each small rectangle is : 1536 : 3 = 512 (cm2)
We have : \(2a.a=512\Leftrightarrow a^2=256\Leftrightarrow a=16\)
The answer is : 16 x 10 = 160 (cm)
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KEITA FC 8C 28/11/2017 at 21:52
Let a (cm) be the width of the small rectangles, then 2a is their length and the perimeter of the rectangle PQRS is : 2(2a + a + 2a) = 10a
The area of each small rectangle is : 1536 : 3 = 512 (cm2)
We have : 2a.a=512⇔a2=256⇔a=162a.a=512⇔a2=256⇔a=16
The answer is : 16 x 10 = 160 (cm)