Given: \(\dfrac{x}{y+z+1}=\dfrac{y}{x+z+2}=\dfrac{z}{x+y-3}=x+y+z\) Calculate: \(A=\dfrac{x^2+y^2+z^2}{x^2-y^2-z^2}\)
Given: \(\dfrac{x}{y+z+1}=\dfrac{y}{x+z+2}=\dfrac{z}{x+y-3}=x+y+z\)
Calculate: \(A=\dfrac{x^2+y^2+z^2}{x^2-y^2-z^2}\)
