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Lạnh Lùng Boy 23/11/2017 at 15:21
a) (x+2)(x−2)−(x−3)(x+1)(x+2)(x−2)−(x−3)(x+1)
=x^2−22−(x^2+x−3x−3)x^2−22−(x^2+x−3x−3)
=x^2−4−x^2−x+3x+3x^2−4−x^2−x+3x+3
=2x−12x−1 ;
b) (2x+1)^2+(3x−1)^2+2(2x+1)(3x−1)(2x+1)^2+(3x−1)^2+2(2x+1)(3x−1)
=(2x+1)^2+2.(2x+1)(3x−1)+(3x−1)^2(2x+1)^2+2.(2x+1)(3x−1)+(3x−1)^2
=[(2x+1)+(3x−1)]^2[(2x+1)+(3x−1)]^2
= (2x+1+3x−1)^2(2x+1+3x−1)^2
=(5x)^2=25x^2
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