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Fake Love

23/11/2017 at 15:19
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Rút gọn các biểu thức sau :

a) (x+2)(x−2)−(x−3)(x+1)(x+2)(x−2)−(x−3)(x+1) ;

b) (2x+1)2+(3x−1)2+2(2x+1)(3x−1)(2x+1)2+(3x−1)2+2(2x+1)(3x−1)




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    Lạnh Lùng Boy 23/11/2017 at 15:21

    a) (x+2)(x−2)−(x−3)(x+1)(x+2)(x−2)−(x−3)(x+1)

    =x^2−22−(x^2+x−3x−3)x^2−22−(x^2+x−3x−3)

    =x^2−4−x^2−x+3x+3x^2−4−x^2−x+3x+3

    =2x−12x−1  ;

    b) (2x+1)^2+(3x−1)^2+2(2x+1)(3x−1)(2x+1)^2+(3x−1)^2+2(2x+1)(3x−1)

    =(2x+1)^2+2.(2x+1)(3x−1)+(3x−1)^2(2x+1)^2+2.(2x+1)(3x−1)+(3x−1)^2

    =[(2x+1)+(3x−1)]^2[(2x+1)+(3x−1)]^2

    = (2x+1+3x−1)^2(2x+1+3x−1)^2

    =(5x)^2=25x^2

    Fake Love selected this answer.

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