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Lê Quốc Trần Anh Coordinator

17/11/2017 at 18:03
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Harvey has a fair eight-sided die that has a different number from 1 to 8 on each side. If he rolls this die twice, what is the probability that the second number rolled is greater than or equal to the first number? Express your answer as a common fraction.




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    Phan Thanh Tinh Coordinator 22/11/2017 at 11:07

    Rolling the die twice can lead to : 8 x 8 = 64 (results)

    There are : \(8+7+6+...+1=\dfrac{8.9}{2}=36\) (results) that the second number rolled is not smaller than the first number 

    The answer is : \(\dfrac{36}{64}=\dfrac{9}{16}\)

    Lê Quốc Trần Anh selected this answer.

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