There are : \(\dfrac{8.7}{2}=28\) choices to choose 2 girls

There are : \(\dfrac{11.10}{2}=55\) choices to choose 2 boys

The answer is : \(28\times55=1540\) (teams)

There are \(4\cdot\dfrac{11\cdot12}{2}=264\left(different-team\right)\)