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Lê Quốc Trần Anh Coordinator

15/11/2017 at 16:57
Answers
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If \(x+\dfrac{4}{x}=y+\dfrac{4}{y}\) and x ≠ y, then what is the value of the product xy?




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  • ...
    Cậu Bé Ngu Ngơ 16/11/2017 at 12:54

    x+4x=y+4yx+4x=y+4y

    ⇔x2+4x=y2+4y⇔x2+4x=y2+4y

    ⇔y(x2+4)=x(y2+4)⇔y(x2+4)=x(y2+4)

    ⇒x2y+4y=xy2+4x⇒x2y+4y=xy2+4x

    ⇒x2y−xy2=4x−4y⇒x2y−xy2=4x−4y

    ⇒xy(x−y)=4(x−y)⇒xy(x−y)=4(x−y)

    ⇒xy(x−y)−4(x−y)=0⇒xy(x−y)−4(x−y)=0

    ⇒(xy−4)(x−y)=0⇒(xy−4)(x−y)=0

    But x ≠ y 

    ⇒xy−4=0⇒xy−4=0

    ⇒xy=4

  • ...
    Dao Trong Luan Coordinator 15/11/2017 at 18:18

    \(x+\dfrac{4}{x}=y+\dfrac{4}{y}\)

    \(\Leftrightarrow\dfrac{x^2+4}{x}=\dfrac{y^2+4}{y}\)

    \(\Leftrightarrow y\left(x^2+4\right)=x\left(y^2+4\right)\)

    \(\Rightarrow x^2y+4y=xy^2+4x\)

    \(\Rightarrow x^2y-xy^2=4x-4y\)

    \(\Rightarrow xy\left(x-y\right)=4\left(x-y\right)\)

    \(\Rightarrow xy\left(x-y\right)-4\left(x-y\right)=0\)

    \(\Rightarrow\left(xy-4\right)\left(x-y\right)=0\)

    But x ≠ y 

    \(\Rightarrow xy-4=0\)

    \(\Rightarrow xy=4\)


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