Lê Quốc Trần Anh Coordinator
15/11/2017 at 16:57-
Cậu Bé Ngu Ngơ 16/11/2017 at 12:54
x+4x=y+4yx+4x=y+4y
⇔x2+4x=y2+4y⇔x2+4x=y2+4y
⇔y(x2+4)=x(y2+4)⇔y(x2+4)=x(y2+4)
⇒x2y+4y=xy2+4x⇒x2y+4y=xy2+4x
⇒x2y−xy2=4x−4y⇒x2y−xy2=4x−4y
⇒xy(x−y)=4(x−y)⇒xy(x−y)=4(x−y)
⇒xy(x−y)−4(x−y)=0⇒xy(x−y)−4(x−y)=0
⇒(xy−4)(x−y)=0⇒(xy−4)(x−y)=0
But x ≠ y
⇒xy−4=0⇒xy−4=0
⇒xy=4
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\(x+\dfrac{4}{x}=y+\dfrac{4}{y}\)
\(\Leftrightarrow\dfrac{x^2+4}{x}=\dfrac{y^2+4}{y}\)
\(\Leftrightarrow y\left(x^2+4\right)=x\left(y^2+4\right)\)
\(\Rightarrow x^2y+4y=xy^2+4x\)
\(\Rightarrow x^2y-xy^2=4x-4y\)
\(\Rightarrow xy\left(x-y\right)=4\left(x-y\right)\)
\(\Rightarrow xy\left(x-y\right)-4\left(x-y\right)=0\)
\(\Rightarrow\left(xy-4\right)\left(x-y\right)=0\)
But x ≠ y
\(\Rightarrow xy-4=0\)
\(\Rightarrow xy=4\)