Let a be the number of jelly beans in the jar.

After Kathy ate, the jar had a−18a=78aa−18a=78a.

Sue ate : 78a×15=740a78a×15=740a

After Sue ate, the jar had : 78a−740a=710a78a−740a=710a

Kathy and Sue ate : a−710a=310aa−710a=310a

Pat ate : 310a×2=35a310a×2=35a

Drew ate : 710a−35a=110a710a−35a=110a

The answer is : 110a:35a=16

Let a be the number of jelly beans in the jar.

After Kathy ate, the jar had \(a-\dfrac{1}{8}a=\dfrac{7}{8}a\).

Sue ate : \(\dfrac{7}{8}a\times\dfrac{1}{5}=\dfrac{7}{40}a\)

After Sue ate, the jar had : \(\dfrac{7}{8}a-\dfrac{7}{40}a=\dfrac{7}{10}a\)

Kathy and Sue ate : \(a-\dfrac{7}{10}a=\dfrac{3}{10}a\)

Pat ate : \(\dfrac{3}{10}a\times2=\dfrac{3}{5}a\)

Drew ate : \(\dfrac{7}{10}a-\dfrac{3}{5}a=\dfrac{1}{10}a\)

The answer is : \(\dfrac{1}{10}a:\dfrac{3}{5}a=\dfrac{1}{6}\)