Summer Clouds moderators
14/11/2017 at 08:53-
Nguyễn Đặng Hoàng Phúc 14/11/2017 at 11:45
Put a,b sequence is the number of toy animals Jerry and Ben have:
Deduced:the legs of toy animals Jerry has is 4a;the legs of toy animals Ben has is 2b
We have:\(\left\{{}\begin{matrix}a-b=10\\4a+2b=220\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}a-b=10\\2a+b=110\end{matrix}\right.\)\(\Rightarrow3a=120\Leftrightarrow a=40\)
So toy animals Jerry has is 40
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1234 này 14/11/2017 at 18:22
Put a,b sequence is the number of toy animals Jerry and Ben have:
Deduced:the legs of toy animals Jerry has is 4a;the legs of toy animals Ben has is 2b
We have:{a−b=104a+2b=220{a−b=104a+2b=220⇔{a−b=102a+b=110⇔{a−b=102a+b=110⇒3a=120⇔a=40⇒3a=120⇔a=40
So toy animals Jerry has is 40
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Let a, b be the number of toy animals Ben has and Jerry has respectively. We have :
\(\left\{{}\begin{matrix}b-a=10\\2a+4b=220\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2b-2a=20\\2b+a=110\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}3a=90\\b=a+10\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=30\\b=40\end{matrix}\right.\)
So, the answer is 40