If n is an even integer such that 0 < n < 10, what is the sum of all possible unit fractions of the form \(\dfrac{1}{n}\) ? Express your answer as a common fraction.
The answer is : \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{8}=\dfrac{25}{24}\)