There are all: \(6\cdot6=36\left(ways\right)\) for the two dice to roll.

The possible ways of the two dice are: 6-5 ; 5-4 ; 4-3 ; 3-2 ; 2-1 and reverse the order

So the probability is: \(\dfrac{5\cdot2}{36}=\dfrac{5}{18}\)

There are all: 6⋅6=36(ways) for the two dice to roll.

The possible ways of the two dice are: 6-5 ; 5-4 ; 4-3 ; 3-2 ; 2-1 and reverse the order

So the probability is: \(\dfrac{5.2}{36}=\dfrac{10}{36}=\dfrac{2}{18}\)