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justin bieber

19/03/2017 at 12:03
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Find the value of xyz if x,y and z satisfy the equations:

\(\left\{{}\begin{matrix}3x-2y=5\\2y+3x=1\\x-z=4\end{matrix}\right.\)


Simulataneous Equation A System of Equations

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  • ...
    Nguyệt Nguyệt 19/03/2017 at 12:07

    3x - 2y = 5
    2y + 3z = 1
    x - z = 4
    We have :
    ( 3x - 2y ) - ( 2y + 3z ) = 5 - 1
    3x - 2y - 2y - 3z = 4
    3x - 4y  - 3z = 4
    3x - 3z - 4y = 4
    3. ( x - z ) - 4y = 4
    3 . 4 - 4y  = 4   ( replace x - z = 4 )
    12 - 4y  = 4
           4y   = 12 - 4
          4y     = 8
            y     = 8 : 4
           y      =  2
    => 3x - 2.2 = 5    ( replace y = 2 )
          3x - 4 = 5
          3x       = 5 + 4
          3x       = 9
            x       = 9 : 3
            x       = 3
    => 3 - z = 4  ( replace x = 3 )
               z  = 3 - 4
                z = -1
        So y = 2, x = 3 and z = -1

    justin bieber selected this answer.
  • ...
    FA KAKALOTS 06/02/2018 at 12:33

    3x - 2y = 5
    2y + 3z = 1
    x - z = 4
    We have :
    ( 3x - 2y ) - ( 2y + 3z ) = 5 - 1
    3x - 2y - 2y - 3z = 4
    3x - 4y  - 3z = 4
    3x - 3z - 4y = 4
    3. ( x - z ) - 4y = 4
    3 . 4 - 4y  = 4   ( replace x - z = 4 )
    12 - 4y  = 4
           4y   = 12 - 4
          4y     = 8
            y     = 8 : 4
           y      =  2
    => 3x - 2.2 = 5    ( replace y = 2 )
          3x - 4 = 5
          3x       = 5 + 4
          3x       = 9
            x       = 9 : 3
            x       = 3
    => 3 - z = 4  ( replace x = 3 )
               z  = 3 - 4
                z = -1
        So y = 2, x = 3 and z = -1



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