Hương Yêu Dấu
25/10/2017 at 14:17-
tth 29/10/2017 at 20:24
Apply the same ratio. We have:
\(\dfrac{a}{6}=\dfrac{b}{3}=\dfrac{c}{12}=\dfrac{a-b+c}{6-3+12}=30\)
<=> \(\dfrac{a-b+c}{15}=30\)
But 30 : 15 = 2
=>\(a=6.2=12\)
=> b = 3 . 2 = 6
=> c = 12 . 2 = 24
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Detecvite Conan 26/10/2017 at 18:26
We have:
a/6=b/3=c/12=a-b+c/6-3+12=30/15=2
a/6=2=>a=12
b/3=2=>b=6
c/12=2=>c=24
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We have: \(\dfrac{a}{6}=\dfrac{b}{3}=\dfrac{c}{12}=\dfrac{a-b+c}{6-3+12}=\dfrac{30}{15}=2\)
=> \(\dfrac{a}{6}=2\) <=> \(a=6\cdot2=12\)
=> \(\dfrac{b}{3}=2\) <=> \(b=3\cdot2=6\)
=> \(\dfrac{c}{12}=2\) <=> \(c=12\cdot2=24\)