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Kaya Renger Coordinator

17/10/2017 at 13:35
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With x + y + z = 0

Show that : x3 + x2z + y2z - xyz + y3 = 0




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    Phan Thanh Tinh Coordinator 17/10/2017 at 18:09

    \(x^3+x^2z+y^2z-xyz+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)+z\left(x^2-xy+y^2\right)\)

    \(=\left(x+y+z\right)\left(x^2-xy+y^2\right)=0\)

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