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Summer Clouds moderators

13/10/2017 at 10:16
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Find x such that \(\left|x+2\right|=\left|3x-1\right|\).




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    Phan Thanh Tinh Coordinator 13/10/2017 at 11:42

    There are 4 cases :

    + \(x< -2\)

    \(-x-2=1-3x\Leftrightarrow2x=3\Leftrightarrow x=\dfrac{3}{2}\) (asburd)

    + \(-2\le x< \dfrac{1}{3}\)

    \(x+2=1-3x\Leftrightarrow4x=-1\Leftrightarrow x=-\dfrac{1}{4}\) (satisfied)

    + \(x\ge\dfrac{1}{3}\)

    \(x+2=3x-1\Leftrightarrow3=2x\Leftrightarrow x=\dfrac{3}{2}\) (satisfied)

    So, \(S=\left\{-\dfrac{1}{4};\dfrac{3}{2}\right\}\)

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