Question by Cristiano Ronaldo - Discuss with MathYouLike

Cristiano Ronaldo

19/03/2017 at 10:46

It given \(A=\dfrac{3000\times3003}{3001\times3002}\),\(B=\dfrac{3000\times3002}{3001\times3003}\)and \(C=\dfrac{3000\times3001}{3002\times3003}\), then

(A) C < B < A

(B) A < C < B

(C) C < A < B

(D) A < B < C

(E) B < A < C

rational numbers

List of answers

FA KAKALOTS 03/02/2018 at 12:46

We have :

3000.30013002.3003<3000.30023002.3003<3000.30023001.3003<3000.30033001.3003<3000.30033001.3002

(because 3000.3001 < 3000.3002 < 3000.3003 ;

3002.3003 > 3001.3003 > 3001.3002)

Hence C < B < A

So the correct answer is (A)
Phan Thanh Tinh Coordinator 23/03/2017 at 18:12

We have :

\(\dfrac{3000.3001}{3002.3003}< \dfrac{3000.3002}{3002.3003}< \dfrac{3000.3002}{3001.3003}< \dfrac{3000.3003}{3001.3003}< \dfrac{3000.3003}{3001.3002}\)

(because 3000.3001 < 3000.3002 < 3000.3003 ;

3002.3003 > 3001.3003 > 3001.3002)

Hence C < B < A

So the correct answer is (A)

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