Cristiano Ronaldo
19/03/2017 at 10:38-
¤« 08/04/2018 at 15:11
We have:
|a−1001|≥0
⇒|a−1000|≥1
⇒|a−1000|+|a−1001|≥1+0=1
=> Smallest value of |a-1000| + |a - 1001| = 1 at:
* a = 1001 and |a-1000| + |a - 1001| = 1 + 0 = 1
* a = 1000 and |a-1000| + |a - 1001| = 0 + 1 = 1
Are you OK?
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Dao Trong Luan 24/07/2017 at 11:51
We have:
\(\left|a-1001\right|\ge0\)
\(\Rightarrow\left|a-1000\right|\ge1\)
\(\Rightarrow\left|a-1000\right|+\left|a-1001\right|\ge1+0=1\)
=> Smallest value of |a-1000| + |a - 1001| = 1 at:
* a = 1001 and |a-1000| + |a - 1001| = 1 + 0 = 1
* a = 1000 and |a-1000| + |a - 1001| = 0 + 1 = 1
Are you OK?
-