Kaya Renger Coordinator
01/10/2017 at 19:57-
Dao Trong Luan 01/10/2017 at 21:57
In a hour, hour needle run slowest. We counted how long after the cycle, minutes and seconds meet again.
We have:
For an hour, hour needle run 1/12 ring
For an hour, minute neddle run 1 ring
Each hour, minute needle faster at hour needle is:
1 - 1/12 = 11/12 [ring]
To meet again, minute needle, hour needle to run more than 1 ring. So the time to meet they again is:
1 : 11/12 = 12/11 [hour]
Same, we have:
For an hour, hour needle run 1/12 ring
For an hour, second needle run 60 ring
Each hour, second needle faster at hour needle is:
60 - 1/12 = 719/12 [ring]
To meet again, second needle, hour needle to run more than 1 ring. So the time to meet they again is:
1 : 719/12 = 12/719 [hour]
So, after: k*12/11 hour, hour needle and minute needle meet.
m*12/719 hour, hour needle and second needle meet.
So, to three needles on a stright light after:
k*12/11 = m*12/719
=> k*719 = m*11
=> After law: 719*12/719 = 12 hour , three needles on a stright