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Kaya Renger Coordinator

01/10/2017 at 19:57
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Can or not if three needles of the clock is located on a straight line . 




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    Dao Trong Luan 01/10/2017 at 21:57

    In a hour, hour needle run slowest. We counted how long after the cycle, minutes and seconds meet again.

    We have:

    For an hour, hour needle run 1/12 ring

    For an hour, minute neddle run 1 ring

    Each hour, minute needle faster at hour needle is:

    1 - 1/12 = 11/12 [ring]

    To meet again, minute needle, hour needle to run more than 1 ring. So the time to meet they again is:

    1 : 11/12 = 12/11 [hour]

    Same, we have:

    For an hour, hour needle run 1/12 ring

    For an hour, second needle run 60 ring

    Each hour, second needle faster at hour needle is:

    60 - 1/12 = 719/12 [ring]

    To meet again, second needle, hour needle to run more than 1 ring. So the time to meet they again is:

    1 : 719/12 = 12/719 [hour]

    So, after: k*12/11 hour, hour needle and minute needle meet. 

    m*12/719 hour, hour needle and second needle meet.

    So, to three needles on a stright light after:

    k*12/11 = m*12/719

    => k*719 = m*11

    => After law: 719*12/719 = 12 hour , three needles on a stright


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