Kaya Renger Coordinator
29/09/2017 at 20:18-
Ngô Tấn Đạt 29/09/2017 at 20:25\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ \Rightarrow2.P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ \Rightarrow2.P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^{16}-1\right)\left(5^{16}+1\right)\\ =5^{32}-1\\ \Rightarrow P=\dfrac{5^{32}-1}{2}\)
Selected by MathYouLike
