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We have: abc + bb = cba.
=> b = 9, a > 5 and c - a = 1 (the only situation satisfy)
So the numbers abc are: 596;697;798
P/s: with \(a\ne b\ne c\) and no proving.
Math You Like selected this answer.
We have: abc + bb = cba.
=> b = 9, a > 5 and c - a = 1 (the only situation satisfy)
So the numbers abc are: 596;697;798
P/s: with \(a\ne b\ne c\) and no proving.
Math You Like selected this answer.