Question by Summer Clouds

15/09/2017 at 08:51

→இے๖ۣۜBoy™†hïếuGîa 16/09/2017 at 13:38

Let p, n, d, q be the number of pennies, nickels, dimes, quarters we need to make 67 cents respectively ( $p, n, d, q \in Z^{+}$ ), then p + 5n + 10d + 25q = 67
Phan Minh Anh 20/09/2017 at 11:57

The answer is 13
Phan Thanh Tinh Coordinator 15/09/2017 at 09:49

Let p, n, d, q be the number of pennies, nickels, dimes, quarters we need to make 67 cents respectively ($p,n,d,q\in Z^+$), then p + 5n + 10d + 25q = 67

We have :

(q ; d ; n ; p) = (2 ; 1 ; 1 ; 2) ; (1 ; 3 ; 2 ; 2) ; (1 ; 3 ; 1 ; 7) ;

(1 ; 2 ; 4 ; 2) ; (1 ; 2 ; 3 ; 7) ; (1 ; 2 ; 2 ; 12) ; (1 ; 2 ; 1 ; 17)

(1 ; 1 ; 6 ; 2) ; (1 ; 1 ; 5 ; 7) ; (1 ; 1 ; 4 ; 12) ; (1 ; 1 ; 3 ; 17) ;

(1 ; 1 ; 2 ; 22) ; (1 ; 1 ; 1 ; 27)

So, the answer is 13