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replace x=1 into the polution above , we have 
p+4q=161 
=> q= (161-p)/4 
=> q=40-(p-1)/4 => q<40(1)
because the p and q are primes so (p-1) divisible for 4 =>p-1 >=4 => p>=5 (2)
Merged (1) with (2) we have q ={2;3;5;7;11;13;17;19;23;29;31}
then you try to the each of case : it will have 2 cases (correct satisfies) 
this case p=37 <=> q=31 and p=133 <=> q=7

i will you to make this topic :)
replace x=1 into the polution above , we have 
p+4q=161 
=> q= (161-p)/4 
=> q=40-(p-1)/4 => q<40(1)
because the p and q are primes so (p-1) divisible for 4 =>p-1 >=4 => p>=5 (2)
Merged (1) with (2) we have q ={2;3;5;7;11;13;17;19;23;29;31}
then you try to the each of case : it will have 2 cases (correct satisfies) 
this case p=37 <=> q=31 and p=133 <=> q=7