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1234 này

05/09/2017 at 10:23
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a(bz-cy)+b(cx-az)+c(ay-bx)=?




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    Math You Like 05/09/2017 at 10:25

    a(bz - cy) + b(cx - az) + c(ay - bx)

    =abz - acy + bcx - abz + acy - bcx

    =0

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